Anti-gravity equation discovered and explained

[Nick Matkin]

Posted by Baby Steps (here)
Sorry what is j? Thanks!

In electronics and power generation j is the square root of minus one and used in calculating complex impedances. (A concept the Quantum Energy Group and HopeGirl should perhaps have grappled with in their 'Free Energy' debacle...)

But I doubt it has the same relevance in this thread.

Nick

[WhiteLove]

Posted by Cristian (here)
Hi,

R in equation no2 is the Earth radius ...right.

So what's the use of equation no3 ?

I don't agree with your equation no2 . F grav =(j *m*v^2)/2R . I don't see how Fgrav can equal that. You have the values for ec. no1 and ec. no2 . Did you do the math and see if they are really equal?

Cristian, thanks for looking into my calculations. R is not the radius of the earth, R = (j * m * v^2) / (2 * Fgrav). I did the math against the real world data and it turned out to be true.

[Cristian]

So what is R on this equation F grav =(j *m*v^2)/2R ?

And how did you come up with this equation? Please explain

Thanks.

[WhiteLove]

Posted by Cristian (here)
So what is R on this equation F grav =(j *m*v^2)/2R ?

And how did you come up with this equation? Please explain

Thanks.

Sure, np.

Erot = 1/2 * j * m * r^2 * w^2
w = v / r
->
Erot = 1/2 * j * m * r^2 * (v / r)^2
->
Erot = 1/2 * j * m * r^2 * v^2 / r^2
->
Erot = (j * m * v^2) / 2
Fgrav = Erot / (Erot / Fgrav)
->
Fgrav = Fgrav = TRUE
->
Fgrav = Erot / (Erot / Fgrav)
->
Fgrav = Erot / (?)
?: R
Unknown distance, R = Erot / Fgrav
->
Fgrav = Erot / (Erot / Fgrav)
Fgrav = Erot / (R)
Erot = Fgrav * R
->
Erot = (j * m * v^2) / 2
Fgrav * R = (j * m * v^2) / 2
->
Fgrav = (j * m * v^2) / (2 * R)

[Cristian]

Wow!

I mean...wow!

Is that even math?

Holy smokes

[WhiteLove]

Posted by Cristian (here)
Wow!

I mean...wow!

Is that even math?

Holy smokes

Heh, I don't know but it is what is turning rotational energy into force of gravity without being able to prove it wrong. Or please do, I have not been able to.