+ Reply to Thread
Results 1 to 13 of 13

Thread: Why UFOs are 94 feet in diameter

  1. Link to Post #1
    Avalon Member
    Join Date
    4th December 2014
    Posts
    1,442
    Thanks
    2,127
    Thanked 8,789 times in 1,357 posts

    Default Why UFOs are 940 feet in diameter

    According to the channeled ET Bashar, you need a toroidal field of energy spinning at 333 kHz in order to make a dimensional shift from physical 3D to non-physical 4D. If that is the case, what would be the diameter of such a craft?

    f = c / (2 * pi * rad)
    f = 333000Hz
    rad = 299792458 / 2092300,7072908022968161204932641
    rad = 143,2836384155237915582251751884
    diameter = 2 * rad
    diameter = 2 * 143,2836384155237915582251751884
    diameter = 286,5672768310475831164503503768 m
    m -> ft
    diameter = 940.181 ~ 940 feet

    EDIT: Please note that my initial calculations were off by a factor of 10, I must have accidentially keyed in the wrong numbers when I inserted the values into the digital calculator, thanks Bill and Paul for pointing that out!
    Last edited by WhiteLove; 30th May 2015 at 07:30.

  2. The Following 2 Users Say Thank You to WhiteLove For This Post:

    Nasu (30th May 2015), Sunny-side-up (30th May 2015)

  3. Link to Post #2
    Avalon Member lucidity's Avatar
    Join Date
    16th September 2014
    Posts
    1,089
    Thanks
    1,029
    Thanked 4,777 times in 956 posts

    Default Re: Why UFOs are 94 feet in diameter

    Hi WhiteLove,

    What is c ?

    I don't mean what value is C, i mean, what is it conceptually?

    why can't any object of any size produce a field of energy of 333KHz ?

    machines that create <whatever> come in all shapes and sizes

    and ... UFOs come in all shapes and all sizes.

    be happy :-)

    lucidity

  4. The Following 4 Users Say Thank You to lucidity For This Post:

    Becky (30th May 2015), Nasu (30th May 2015), shadowstalker (30th May 2015), sigma6 (31st May 2015)

  5. Link to Post #3
    New Zealand Unsubscribed
    Join Date
    1st September 2011
    Posts
    5,984
    Thanks
    34,888
    Thanked 38,520 times in 5,690 posts

    Default Re: Why UFOs are 94 feet in diameter

    Some it would seem, are based on a harmonic of "9's" but Lucidity is right - they come in all shapes and sizes - Earth's systems of measurement (ie imperical or metric) don't necessarily equate well together either!

  6. Link to Post #4
    Canada Avalon Member DeDukshyn's Avatar
    Join Date
    22nd January 2011
    Location
    From 100 Mile House ;-)
    Language
    English
    Age
    50
    Posts
    9,394
    Thanks
    29,779
    Thanked 45,466 times in 8,541 posts

    Default Re: Why UFOs are 94 feet in diameter

    Quote Posted by lucidity (here)
    Hi WhiteLove,

    What is c ?

    I don't mean what value is C, i mean, what is it conceptually?

    why can't any object of any size produce a field of energy of 333KHz ?

    machines that create <whatever> come in all shapes and sizes

    and ... UFOs come in all shapes and all sizes.

    be happy :-)

    lucidity
    The speed of light, perhaps?
    When you are one step ahead of the crowd, you are a genius.
    Two steps ahead, and you are deemed a crackpot.

  7. The Following User Says Thank You to DeDukshyn For This Post:

    shadowstalker (30th May 2015)

  8. Link to Post #5
    UK Avalon Founder Bill Ryan's Avatar
    Join Date
    7th February 2010
    Location
    Ecuador
    Posts
    34,425
    Thanks
    211,552
    Thanked 459,739 times in 32,946 posts

    Default Re: Why UFOs are 94 feet in diameter

    -------

    1) Where does this equation come from?
    Quote f = c / (2 * pi * rad)
    2) I checked the calculation, and I make the diameter just over 940 ft (286 m). I think you're out by a factor of 10. (That's fairly large for a small craft such are very often seen. Maybe we should blame Bashar!)

  9. The Following 11 Users Say Thank You to Bill Ryan For This Post:

    ChristianSky (30th May 2015), DeDukshyn (1st June 2015), Jean-Marie (30th May 2015), justntime2learn (30th May 2015), Lifebringer (30th May 2015), Nasu (30th May 2015), Omni (30th May 2015), regnak (30th May 2015), shadowstalker (30th May 2015), sigma6 (31st May 2015), WhiteLove (30th May 2015)

  10. Link to Post #6
    United States Administrator ThePythonicCow's Avatar
    Join Date
    4th January 2011
    Location
    North Texas
    Language
    English
    Age
    76
    Posts
    28,643
    Thanks
    30,557
    Thanked 138,799 times in 21,552 posts

    Default Re: Why UFOs are 94 feet in diameter

    c is the speed of light in a vacuum, and is perhaps best known for its appearance in the fabled equation E = mc^2. The value of c, as shown in the first post above, is 299792458 meters/sec.

    I suppose that the equation f = c / (2 * pi * rad) reflects Baskar's assumption that he's looking for the radius of a circle of sufficient size such that light could traverse the circumference of that circle f == 333,000 times per second. The equation realizes that something going around a circumference of (2 * pi * rad) some (f) times per second would have to travel at a velocity of f * 2 * pi * rad. If one assumes that velocity is the speed of light c, then one can solve for rad (radius), and hence for the diameter (2 * rad):
    diameter == c / (pi * f) == 299792458 / (3.1415965 * 333000) == 286.5669 meters.
    Multiply that by 3.28084 feet/meters to convert to feet: 286.5669 * 3.28084 == 940.18 feet (not 94 feet!)

    In other words:
    If light can traverse 299792458 meters in a second, then it can traverse 299792458 / 333000 == 900.2 meters in 1 / 333,000 seconds. A craft with a circumference of 900.2 meters would have a diameter of 900.2 / pi == 900.2 / 3.1415 == 286.551 meters, which is 940.14 feet (not the 94 feet claimed.)
    So, like Bill, I am getting a result that is off by a factor of 10.

    (Note: I'm American, not British, so I use the comma ',' to separate thousands, not as a decimal point ... sorry <grin>.)
    Last edited by ThePythonicCow; 30th May 2015 at 05:52.
    My quite dormant website: pauljackson.us

  11. The Following 6 Users Say Thank You to ThePythonicCow For This Post:

    Agape (30th May 2015), Bill Ryan (30th May 2015), kanishk (31st May 2015), Nasu (30th May 2015), Omni (30th May 2015), WhiteLove (30th May 2015)

  12. Link to Post #7
    United States Administrator ThePythonicCow's Avatar
    Join Date
    4th January 2011
    Location
    North Texas
    Language
    English
    Age
    76
    Posts
    28,643
    Thanks
    30,557
    Thanked 138,799 times in 21,552 posts

    Default Re: Why UFOs are 94 feet in diameter

    The third line of the calculation in the opening post seems to be off by a factor of 10:
    rad = 299792458 / 20941856,628829561727591980792941
    This line presumably comes from solving the first line for 'rad':
    rad = c / (2 * pi * f)
    Substituting c == 299792458, pi == 3.14159265, and f == 333000, I get (2 * pi * f) == (2 * 3.14159265 * 333000) == 2092300, yielding a corrected third line of:
    rad == 299792458 / 2092300
    Not:
    rad == 299792458 / 20941856
    The 20941856 (from the waaaay over specified as 20941856,628829561727591980792941) in the opening post is about ten times the value of 2092300 that it should be, and (since it is in the denominator) calculates a resulting size that is about one-tenth of what it should be.

    ... a classic example of hiding a miscalculation with excess precision: 628829561727591980792941 (24 decimal digits of precision ... jeez), along with unnecessary complications (flipping between radius and diameter, thus introducing cancelling factors of two, when the simpler equation would have stayed with the desired result of diameter:
    diameter = c / (pi * f)
    Last edited by ThePythonicCow; 30th May 2015 at 05:56.
    My quite dormant website: pauljackson.us

  13. The Following 4 Users Say Thank You to ThePythonicCow For This Post:

    Bill Ryan (30th May 2015), kanishk (31st May 2015), Nasu (30th May 2015), WhiteLove (30th May 2015)

  14. Link to Post #8
    Avalon Member lucidity's Avatar
    Join Date
    16th September 2014
    Posts
    1,089
    Thanks
    1,029
    Thanked 4,777 times in 956 posts

    Default Re: Why UFOs are 94 feet in diameter

    Hi Paul,

    Just two points.

    First: You said:
    (Note: I'm American, not British, so I use the comma ',' to separate thousands, not as a decimal point ... sorry <grin>.)

    British people don't use a comma to denote a decimal point.
    American people, do it the way the British people do;
    using full stops for decimal points, and commas to denote a series of three numbers.
    (Europeans however, are different).

    Second,
    (a) I have an mp3 player that plays the Schumann resonance at 7.83 Hz. What size is it?
    (b) Does it change size when it plays a frequency of 33Hz ?


    be happy :-)

    lucidity

  15. The Following User Says Thank You to lucidity For This Post:

    Nasu (30th May 2015)

  16. Link to Post #9
    Avalon Member
    Join Date
    4th December 2014
    Posts
    1,442
    Thanks
    2,127
    Thanked 8,789 times in 1,357 posts

    Default Re: Why UFOs are 94 feet in diameter

    Quote Posted by Bill Ryan (here)
    -------
    1) Where does this equation come from?
    Quote f = c / (2 * pi * rad)
    2) I checked the calculation, and I make the diameter just over 940 ft (286 m). I think you're out by a factor of 10. (That's fairly large for a small craft such are very often seen. Maybe we should blame Bashar!)
    Like 3 football fields, thanks Bill, you're absolutely right! (I edited the original post)

    1) Where does this equation come from? f = c / (2 * pi * rad)

    Paul had a great explanation on this, he is in my view right in his explanation. This formula was extracted from one of Bashar's channeling sessions, where he pointed out that earth's frequency is 7,5 Hz (299792458 / 40075000). Since this is the proposed frequency of earth, I thought that in order to make a different object - such as a UFO - spinning at 333 kHz, it would have to follow the same formula and that would allow for the measurement of the diameter of a UFO. When I checked if this could be true relative to my own calculations I did on my own theory of gravity (available here), it actually fit right into my own calculations too. So my current understanding is that f = c / (2 * pi * rad) could be accurate. Please note that Bashar is not including mass (m) and energy (E) in his planet frequency calculation. He is basically saying that each body in our dimension is unique and has a unique frequency due to their circumference relative to the speed of light. I think that speed of light is probably different at different dimensions, because obviously as light travels it must travel slower when it passes through a more heavy density/thicker environment. And if THAT is the case, it would make every object in creation having a unique frequency, which is quite interesting if it is a location in time and space, which is what Bashar claims. Following that reasoning, what you do to travel between galaxies, is to escape the thick density of the physical dimension. And this Bashar claims happens by spinning a toroidal electromagnetic field at 333 kHz in two directions and depending on these directions you would have an electromagnetic energy output that when at the level when it cancels the mass of the craft at 333 kHz (which depends on the two directions of the flow of the electromagnetic energy field) equals the target destination. That's how I understand his explanation.
    Last edited by WhiteLove; 30th May 2015 at 09:22.

  17. The Following 3 Users Say Thank You to WhiteLove For This Post:

    Bill Ryan (30th May 2015), kanishk (31st May 2015), Nasu (30th May 2015)

  18. Link to Post #10
    Ireland On Sabbatical regnak's Avatar
    Join Date
    28th September 2014
    Posts
    374
    Thanks
    1,117
    Thanked 1,573 times in 356 posts

    Default Re: Why UFOs are 94 feet in diameter

    okay channels lie tell half truth

    Walter Russell ( who was a channel ) craft can be any and all shapes but the reason they favour some shapes is that temperature density and pressure changes the shape of metal see post on memory when heated the metal return to a certain shape no matter how twisted

    http://www.bbc.com/news/science-environment-32886000

    craft are made by Magnesium aluminate called spinal armour it is the future impossible to crack it can be chipped by bullets barely

    http://www.rexresearch.com/spinel/sanghera.html

    How are the craft powered look closely how gravity works from Walter Russell then engineer it for the ship it is a completely independent system a hint look at a weather map with all high pressure and low pressure systems

    The length of the ship depends on the harmonic of reality see the work of Bruce Cathie ( Deceased )but most of the ships do not enter our atmospheric all the real ships you see are small scout craft

    Most of the ET technology we have already there are some very exotic stuff we do not have most because they do not want to spend time our money on something stupid

    The powers that be conclusion it is scary out there and even here on Earth
    Last edited by regnak; 30th May 2015 at 14:56.

  19. The Following 2 Users Say Thank You to regnak For This Post:

    Nasu (30th May 2015), WhiteLove (30th May 2015)

  20. Link to Post #11
    Avalon Member
    Join Date
    4th December 2014
    Posts
    1,442
    Thanks
    2,127
    Thanked 8,789 times in 1,357 posts

    Default Re: Why UFOs are 94 feet in diameter

    Quote Posted by jonsnow (here)
    but most of the ships do not enter our atmospheric all the real ships you see are small scout craft
    Makes sense. When the frequency goes up, the radius of the object goes down - at least when it comes to planetary bodies, as described by Bashar. It's quite possible that these smaller scout crafts cancel the gravity at higher frequencies in the physical dimension and before they make the dimensional shift they return to their much bigger mothership. Another possibility is that it's only the electromagnetic toroidal field that needs to be in the size of 3 football fields, and that the UFO can be much smaller in its diameter. The UFO I have witnessed was roughly at the size of 3 football fields, it was huge.

    I am going to try to find information on how large Bashar claims UFOs are...
    Last edited by WhiteLove; 30th May 2015 at 12:37.

  21. The Following 2 Users Say Thank You to WhiteLove For This Post:

    kanishk (31st May 2015), Nasu (30th May 2015)

  22. Link to Post #12
    Ireland On Sabbatical regnak's Avatar
    Join Date
    28th September 2014
    Posts
    374
    Thanks
    1,117
    Thanked 1,573 times in 356 posts

    Default Re: Why UFOs are 94 feet in diameter

    Look up the work of Walter Russell the universe is rather simple only two processes one creating and one destroying .It is quite cool how simple it works are our most of science theory's are wrong this effect occurs everywhere his lifework is truly great

    The future fuel is hydrogen then light or so he says interesting

    if you change the frequencies , pressure , or density you change the element
    Last edited by regnak; 30th May 2015 at 10:12.

  23. The Following 2 Users Say Thank You to regnak For This Post:

    Nasu (30th May 2015), WhiteLove (30th May 2015)

  24. Link to Post #13
    Avalon Member
    Join Date
    4th December 2014
    Posts
    1,442
    Thanks
    2,127
    Thanked 8,789 times in 1,357 posts

    Default Re: Why UFOs are 94 feet in diameter

    Quote Posted by jonsnow (here)
    Look up the work of Walter Russell the universe is rather simple only two processes one creating and one destroying .It is quite cool how simple it works are our most of science theory's are wrong this effect occurs everywhere his lifework is truly great

    The future fuel is hydrogen then light or so he says interesting.
    I'll check him out, thanks man!

+ Reply to Thread

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts