Mathematician WANTED!

[Thinker]

Mathematician WANTED!

I am looking for a mathematician who is willing to solve the resonance frequency equation used in the Stanley Meyer electrolysis experiment.

The Experiment:
Stanley Meyer made an LC resonant circuit using 304 Stainless Steel and H2O as a Capacitor (C) and a Coil of wire as an Inductor (L). He tuned the LC circuit with a variable inductor for 120Hz and added a Duty Cycle to regulate power consumption and heat. He charged the LC circuit with more than 20KV using a Flyback Transformer.


http://www.fotothing.com/photos/9fd/9fd02f4437b8e6672823b6bbe428282f.jpg

Problem:
Solve for the inductance value (L) for a given frequency (f) of 120Hz DC and a capacitance (C) based on a 6” long capacitor as describe below.

Capacitor:
Two concentric 304 SS tubes submerged in tap water as the electrolytic. The inner tube has an OD of 1” and a gap between the inner and outer of 0.060”


http://www.fotothing.com/photos/ec7/ec7977eaa00293bca7c5ac39a5f97aac.jpg

Inductor:
The inductor is a coil of wire wrapped around a ferries steel rod to produce the inductance required.


http://www.fotothing.com/photos/3cd/3cd14e92fddecbd1381ab2f727151966_cc3.jpg

[Tuza]

I am sure it wouldn't take long for someone like Nassim to figure out. :confused:

[Anchor]

I had to get my electronics book out :)

Resonant frequency f, Inductance L and Capacitance C

f=0.159/√(LC)

If you are trying to reverse engineer the circuit, then I suppose you need to make a capacitor the way he did and measure it. Then knowing the capacitance and the target resonant frequency (120Hz by the look of it) you can get the value of L.

What are you trying to do? In fact what was he trying to do?

[Houman]

Don't think in terms of classical resonance but in terms of parametric resonance...
Houman

[Agape]

To me it looks like linear circuit with two inductors and one capacitor , ok not, it's one inductor and transformer and capacitor . Anyway , there's linear relationship between the three saying that I (C) = I (T) + I (I) - sin (w t) and w(omega)=2Pi f where I is the current of capacitor , transformer and inductor respectively and omega is angular frequency .

So guess if you want to solve it for 120 Hz frequency you'll have to substitute those members.



I'm sure there's some more trick in that but i'm bit lazy to think .

[Tuza]

Right on Eva, but don't tire yourself out too much I do worry about you hon. Take it easy. xxoo

[Thinker]

One of the problems I am having is measuring the capacitance (C). The meter is not expecting water as the dielectric. So, for starters I don't know the actual value of (C). I'm a great fabricator and pretty good programmer, but I don't trust my Algebra skills. Please do it for me, and show how you got there.


http://www.fotothing.com/photos/87d/87d510fe4516ad53841e1ee7ea9286d2.jpg

The result is supposed to be more H2 per Amp. than any other form of electrolysis. Meyer’s claimed to run his dune buggy on the HHO produced.



http://www.youtube.com/watch?v=KttGfktTDf4

[Anchor]

Ah. Snag.

If the water is being rapidly electrolyzed, this will change the dielectric properties and therefore the capacitance.

I see why the variable inductor was so important.

I cant show you how that formula was derived. It just got it out a book. Sorry.