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11th January 2015 13:24
Link to Post #1
Anti-gravity equation discovered and explained
Here is the anti-gravity equation that I've discovered, along with an explanation. Please enjoy! 
1)
Fgrav = (G * m * M) / r^2
2)
Fgrav = (j * m * v^2) / (2 * R)
3)
R = (j * m * v^2) / (2 * Fgrav)
4)
Felec = (q * Q) / (4 * pi * e * r^2)
5)
(2)Fgrav = (4)Felec
(j * m * v^2) / (2 * R) = (q * Q) / (4 * pi * e * r^2)
m = (2 * R * q * Q) / (j * v^2 * 4 * pi * e * r^2)
6)
(1)Fgrav = (G * m * M) / r^2
Fgrav = (M * G * R * q * Q) / (r^4 * j * v^2 * 2 * pi * e)
7)
(3)R = (j * m * v^2) / (2 * Fgrav)
Fgrav^2 = (M * G * j * m * v^2 * q * Q) / (4 * pi * e * j * r^4 * v^2)
8.1)
Fgrav = root ((M * G * j * m * v^2 * q * Q) / (4 * pi * e * j * r^4 * v^2))
Fgrav = root ((G * m * M * q * Q) / (4 * pi * e * r^4))
8.2)
or since Fgrav = m * a
Fgrav = (G * M * q * Q) / (4 * pi * e * r^4 * a)
where
G = Newton's universal gravitational constant
m = Mass of object 1
M = Mass of object 2
q = Charge of object 1
Q = Charge of object 2
e = Permittivity of space
r = Distance between object 1 and object 2
9)
Like charges repel
10)
Unlike charges attract
11)
Gravity
(8.1)Fgrav = root ((G * m * M * q * Q) / (4 * pi * e * r^4))
or
(8.2)Fgrav = (G * M * q * Q) / (4 * pi * e * r^4 * a)
where q and Q are (10) unlike charges that attract
12)
Anti-gravity
(8.1)Fantigrav = root ((G * m * M * q * Q) / (4 * pi * e * r^4))
or
(8.2)Fantigrav = (G * M * q * Q) / (4 * pi * e * r^4 * a)
where q and Q are (9) like charges that repel
In other words, Isaac Newton's force of universal law of gravity A can be joined with the electric force as definied by coulomb's law B, in a direct relationship as root (A * B). Here I am demonstrating this relationship through the force of rotational energy.
13)
The magnetic force is F = qv x B, so that's the next force to get into that equation. It might be root(root((G * m * M * q^3 * Q * v^2) / (4 * pi * e * r^4)) x B). From (8.2)Fgrav = m * a, we can then simplify the equation as:
Fgrav = root((G * m * M * q^3 * Q * v^2) / (4 * pi * e * r^4)) / (m * a) x B
which in turn can be simplified as:
Fgrav = (1 x B) * ((G * M * q^3 * Q * v^2) / (4 * pi * e * r^4 * a) x B)
So in conjunction with the magnetic force, the mass of one of the objects does not impact on the gravity/anti-gravity. Very interesting! If this is true Newton's universal law of gravitation is true only in an environment without a magnetic force present impacting on it, because the magnetic force according to the equation appears to make one of the object's weightless, meaning that object under such condition then has no inherent mass. This strongly indicates that a key to reaching anti-gravity much easier is by also taking advantage of the magnetic force in the anti-gravity solution. This could help explain why you can have those huge motherships/planets being operated by anti-gravity.
14)
This in turn >>might<< be simplified as:
Fgrav = (G * M * q^3 * Q * v^2) / (4 * pi * e * r^4 * a) x B^2
I am not sure if this is a valid mathematical simplification of a cross product though. Please when possible correct this! 
15)
If the above is correct, it would mean the following:
Fgrav = (G * M * q^3 * Q * v^2) / (4 * pi * e * r^4 * a) x B^2
->
Fgrav = (Fnewtongrav * Felec * Fmagn^2) / (m * a)
->
Fgrav = (Fnewtongrav * Felec * Fmagn^2) / (Fnewtongrav)
because the only component missing in the equation from being able to express Fnewtongrav is m and because we can add an imaginary component m of any value in a division without distorting the value, similar to 2/2 = (2m)/(2m) , we can insert m on both sides of the / sign to complete the Fnewtongrav component and hence get rid of the entire Newton universal law of gravitation component from the whole equation.
In other words, Isaac Newton's universal law of gravitation is rendered obsolete by combining the electric and magnetic force in the relationship:
Fgrav = Felec * Fmagn^2
or
Fgrav = (q * Q) / (4 * pi * e * r^2) * (q * v)^2 x B^2
This would yield an electromagnetic gravity/anti-gravity force, where the polarity relationship between the objects would describe whether the two attract (force of gravity) or repel (force of anti-gravity). This force shows that you can achieve anti-gravity through the electromagnetic anti-gravity force without having to care about the masses of the objects directly, no matter their inherent or relative masses, they will still attract or repel.
16)
The frequency of the peak anti-gravity force one can calculate from v = 2 * pi * f * r -> f = v / (2 * pi * r).
Hence, the most simplified anti-gravity formula becomes:
Fantigrav = (q^3 * Q * pi * f^2) / e x B^2
where q and Q are (9) like charges that repel
In order to make a UFO levitate - earth has a negative charge of about half a million coulombs - you would charge the UFO with a negative charge. Furthermore, in order to lessen this charge requirement, you would use magnetism. Nikola Tesla has proved that as the potential increases, so does the magnetism. So there is a mutual relationship between the two, as the above equations also indicate. The force to overcome at earth's surface is ~58.6 * 10^24 N. Exactly what kind of electrical design you would take advantage of when designing this kind of UFO you can speculate on, but logically you would want this craft to not turn into an enormously warm object with high radition levels but rather maintain its temperature at "possible" levels inside the craft. Since the gravity weakens as you get farther and farther away from the earth's core - as can be understood by r^2 in Newton's universal law of gravitation equation N = (G * m * M) / r^2, the starting point at the surface of the earth is the most critical, as you get higher and higher up the temperature also drops, which helps to cool down the object. You would probably want to do UFO testing at the north pole.
Last edited by WhiteLove; 12th January 2015 at 23:03.
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11th January 2015 15:35
Link to Post #2