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29th May 2015 21:59
Link to Post #1
Why UFOs are 940 feet in diameter
According to the channeled ET Bashar, you need a toroidal field of energy spinning at 333 kHz in order to make a dimensional shift from physical 3D to non-physical 4D. If that is the case, what would be the diameter of such a craft?
f = c / (2 * pi * rad)
f = 333000Hz
rad = 299792458 / 2092300,7072908022968161204932641
rad = 143,2836384155237915582251751884
diameter = 2 * rad
diameter = 2 * 143,2836384155237915582251751884
diameter = 286,5672768310475831164503503768 m
m -> ft
diameter = 940.181 ~ 940 feet
EDIT: Please note that my initial calculations were off by a factor of 10, I must have accidentially keyed in the wrong numbers when I inserted the values into the digital calculator, thanks Bill and Paul for pointing that out!
Last edited by WhiteLove; 30th May 2015 at 07:30.
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29th May 2015 23:42
Link to Post #2
Avalon Member
Re: Why UFOs are 94 feet in diameter
Hi WhiteLove,
What is c ?
I don't mean what value is C, i mean, what is it conceptually?
why can't any object of any size produce a field of energy of 333KHz ?
machines that create <whatever> come in all shapes and sizes
and ... UFOs come in all shapes and all sizes.
be happy :-)
lucidity
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The Following 4 Users Say Thank You to lucidity For This Post:
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29th May 2015 23:52
Link to Post #3